What is the derivative of 2x^2-5x+1 ?

The derivative of 2x^2-5x+1 is 4x-5

What is the first derivative of 2x^2-5x+1 ?

The first derivative of 2x^2-5x+1 is 4x-5

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\frac{d}{d x} (2 x^{2} - 5 x + 1)

4 x - 5

Solution steps

\frac{d}{d x} (2 x^{2} - 5 x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) - \frac{d}{d x} (5 x) + \frac{d}{d x} (1)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (5 x) = 5

\frac{d}{d x} (1) = 0

= 4 x - 5 + 0

Simplify

= 4 x - 5

y^{^{'}} + 3 x^{- 1} y = x^{2}

\int_{1}^{2} x^{4} ln (x) d x

\frac{\partial}{\partial x} (y^{2} tan (x y))

5 e^{2 x}

\frac{d}{d x} (6 x^{- 1})

What is the derivative of 2x^2-5x+1 ?
The derivative of 2x^2-5x+1 is 4x-5
What is the first derivative of 2x^2-5x+1 ?
The first derivative of 2x^2-5x+1 is 4x-5