What is the derivative of (sqrt(x)-6)/(sqrt(x)+6) ?

The derivative of (sqrt(x)-6)/(sqrt(x)+6) is 6/(sqrt(x)(\sqrt{x)+6)^2}

What is the first derivative of (sqrt(x)-6)/(sqrt(x)+6) ?

The first derivative of (sqrt(x)-6)/(sqrt(x)+6) is 6/(sqrt(x)(\sqrt{x)+6)^2}

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derivative of

\frac{x - 6}{x + 6}

\frac{6}{x ( x + 6 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x - 6}{x + 6})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x - 6 ) ( x + 6 ) - \frac{d}{d x} ( x + 6 ) ( x - 6 )}{( x + 6 ) ^{2}}

\frac{d}{d x} (x - 6) = \frac{1}{2 x}

\frac{d}{d x} (x + 6) = \frac{1}{2 x}

= \frac{\frac{1}{2 x} ( x + 6 ) - \frac{1}{2 x} ( x - 6 )}{( x + 6 ) ^{2}}

Simplify

\frac{\frac{1}{2 x} ( x + 6 ) - \frac{1}{2 x} ( x - 6 )}{( x + 6 ) ^{2}} : \frac{6}{x ( x + 6 ) ^{2}}

= \frac{6}{x ( x + 6 ) ^{2}}

\frac{d}{d t} (\frac{cosh ( t )}{cosh ( 2 t ) + 1})

f (x) = \frac{x ^{2} + 3}{x}

7 + 3 t + 2 t^{2} - 5 t^{3}

\frac{d}{d x} (\frac{4}{x + 7})

\frac{d y}{d t} = 2 y - 1

What is the derivative of (sqrt(x)-6)/(sqrt(x)+6) ?
The derivative of (sqrt(x)-6)/(sqrt(x)+6) is 6/(sqrt(x)(\sqrt{x)+6)^2}
What is the first derivative of (sqrt(x)-6)/(sqrt(x)+6) ?
The first derivative of (sqrt(x)-6)/(sqrt(x)+6) is 6/(sqrt(x)(\sqrt{x)+6)^2}