What is the derivative of 1+ln(x) ?

The derivative of 1+ln(x) is 1/x

What is the first derivative of 1+ln(x) ?

The first derivative of 1+ln(x) is 1/x

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\frac{d}{d x} (1 + ln (x))

\frac{1}{x}

Solution steps

\frac{d}{d x} (1 + ln (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) + \frac{d}{d x} (ln (x))

\frac{d}{d x} (1) = 0

\frac{d}{d x} (ln (x)) = \frac{1}{x}

= 0 + \frac{1}{x}

Simplify

= \frac{1}{x}

\frac{d}{d x} ((2 x^{3} - 3 x + 1) (x^{2} + 5 x))

i = 1 \sum \infty 3 (\frac{1}{4})^{i - 1}

\int_{0}^{1} e^{x} tan (e^{x}) d x

x \to \infty + lim (3^{- x})

x \to 1 lim (\frac{in ( x )}{x - 1})

What is the derivative of 1+ln(x) ?
The derivative of 1+ln(x) is 1/x
What is the first derivative of 1+ln(x) ?
The first derivative of 1+ln(x) is 1/x