What is the solution for (dy}{dx}=\frac{x^2-2y)/x ,y(2)=2 ?

The solution for (dy}{dx}=\frac{x^2-2y)/x ,y(2)=2 is y=(x^2)/4+4/(x^2)

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(dy}{dx}=\frac{x^2-2y)/x ,y(2)=2

\frac{d y}{d x} = \frac{x ^{2} - 2 y}{x}, y (2) = 2

y = \frac{x ^{2}}{4} + \frac{4}{x ^{2}}

Solution steps

\frac{d y}{d x} = \frac{x ^{2} - 2 y}{x}

Solve linear ODE:

y = \frac{x ^{2}}{4} + \frac{4}{x ^{2}}

y = \frac{x ^{2}}{4} + \frac{4}{x ^{2}}

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What is the solution for (dy}{dx}=\frac{x^2-2y)/x ,y(2)=2 ?
The solution for (dy}{dx}=\frac{x^2-2y)/x ,y(2)=2 is y=(x^2)/4+4/(x^2)