What is the derivative of (x^3/9+3/(4x)) ?

The derivative of (x^3/9+3/(4x)) is (x^2)/3-3/(4x^2)

What is the first derivative of (x^3/9+3/(4x)) ?

The first derivative of (x^3/9+3/(4x)) is (x^2)/3-3/(4x^2)

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\frac{d}{d x} (\frac{x ^{3}}{9} + \frac{3}{4 x})

\frac{x ^{2}}{3} - \frac{3}{4 x ^{2}}

Solution steps

\frac{d}{d x} (\frac{x ^{3}}{9} + \frac{3}{4 x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{x ^{3}}{9}) + \frac{d}{d x} (\frac{3}{4 x})

\frac{d}{d x} (\frac{x ^{3}}{9}) = \frac{x ^{2}}{3}

\frac{d}{d x} (\frac{3}{4 x}) = - \frac{3}{4 x ^{2}}

= \frac{x ^{2}}{3} - \frac{3}{4 x ^{2}}

9 (x^{3} - x), 0

t^{2} e^{5 t}

y = x, y = x^{3}

n = 0 \sum \infty n (\frac{1}{3})^{n}

What is the derivative of (x^3/9+3/(4x)) ?
The derivative of (x^3/9+3/(4x)) is (x^2)/3-3/(4x^2)
What is the first derivative of (x^3/9+3/(4x)) ?
The first derivative of (x^3/9+3/(4x)) is (x^2)/3-3/(4x^2)