What is (\partial)/(\partial x)(2x-cos(y)) ?

The answer to (\partial)/(\partial x)(2x-cos(y)) is 2

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(\partial)/(\partial x)(2x-cos(y))

\frac{\partial}{\partial x} (2 x - cos (y))

2

Solution steps

\frac{\partial}{\partial x} (2 x - cos (y))

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 x) - \frac{\partial}{\partial x} (cos (y))

\frac{\partial}{\partial x} (2 x) = 2

\frac{\partial}{\partial x} (cos (y)) = 0

= 2 - 0

Simplify

= 2

\frac{d}{d x} (\frac{sin ( x )}{1 - sin ( x )})

\frac{\partial}{\partial y} (25 - x^{2} - 5 y)

\int 6 x 1 + x^{2} d x

y^{^{''}} + 20 y^{^{'}} + 500 y = 0

x d y + y d x = 0

What is (\partial)/(\partial x)(2x-cos(y)) ?
The answer to (\partial)/(\partial x)(2x-cos(y)) is 2