What is the derivative of 2/((1-x^3)) ?

The derivative of 2/((1-x^3)) is 6/((1-x)^4)

What is the first derivative of 2/((1-x^3)) ?

The first derivative of 2/((1-x^3)) is 6/((1-x)^4)

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\frac{d}{d x} (\frac{2}{( 1 - x ) ^{3}})

\frac{6}{( 1 - x ) ^{4}}

Solution steps

\frac{d}{d x} (\frac{2}{( 1 - x ) ^{3}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (\frac{1}{( 1 - x ) ^{3}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 2 \frac{d}{d x} ((1 - x)^{- 3})

Apply the chain rule:

- \frac{3}{( 1 - x ) ^{4}} \frac{d}{d x} (1 - x)

= - \frac{3}{( 1 - x ) ^{4}} \frac{d}{d x} (1 - x)

\frac{d}{d x} (1 - x) = - 1

= 2 (- \frac{3}{( 1 - x ) ^{4}} (- 1))

Simplify

2 (- \frac{3}{( 1 - x ) ^{4}} (- 1)) : \frac{6}{( 1 - x ) ^{4}}

= \frac{6}{( 1 - x ) ^{4}}

\int_{0}^{1} 5 (1 + x)^{6} d x

\frac{\partial}{\partial x} (x y e^{x z})

\frac{d}{d x} (arcsec (\frac{1}{x}))

x \to - 4 lim (3 x^{2} - 4 x + 8)

\frac{\partial}{\partial z} (x^{\frac{y}{z}})

What is the derivative of 2/((1-x^3)) ?
The derivative of 2/((1-x^3)) is 6/((1-x)^4)
What is the first derivative of 2/((1-x^3)) ?
The first derivative of 2/((1-x^3)) is 6/((1-x)^4)