What is (\partial)/(\partial x)(-3y^2) ?

The answer to (\partial)/(\partial x)(-3y^2) is 0

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(\partial)/(\partial x)(-3y^2)

\frac{\partial}{\partial x} (- 3 y^{2})

0

Solution steps

\frac{\partial}{\partial x} (- 3 y^{2})

Treat

y

as a constant

Derivative of a constant:

\frac{d}{d x} (a) = 0

= 0

\frac{d}{d x} (lo g_{10} (\frac{x ^{2} - 1}{x}))

\int (ln (x)) (sin (x)) d x

\frac{d r}{d θ} cot (θ) - r = 2

f (x) = x^{2} - 8, (- 4, 8)

\int_{1}^{4} - 8 t ln (t) d t

What is (\partial)/(\partial x)(-3y^2) ?
The answer to (\partial)/(\partial x)(-3y^2) is 0