What is the derivative of x^3+3x^2-9x+1 ?

The derivative of x^3+3x^2-9x+1 is 3x^2+6x-9

What is the first derivative of x^3+3x^2-9x+1 ?

The first derivative of x^3+3x^2-9x+1 is 3x^2+6x-9

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\frac{d}{d x} (x^{3} + 3 x^{2} - 9 x + 1)

3 x^{2} + 6 x - 9

Solution steps

\frac{d}{d x} (x^{3} + 3 x^{2} - 9 x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) + \frac{d}{d x} (3 x^{2}) - \frac{d}{d x} (9 x) + \frac{d}{d x} (1)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (9 x) = 9

\frac{d}{d x} (1) = 0

= 3 x^{2} + 6 x - 9 + 0

Simplify

= 3 x^{2} + 6 x - 9

\frac{d}{d x} (e^{8 - x})

\int \frac{1}{x ^{2} + 6 x + 45} d x

\frac{d}{d x} (\frac{1}{( 5 + x ) ^{2}})

\int \frac{1}{( t ^{2} - 1 ) ^{2}} d t

n = 1 \sum \infty \frac{4}{4 n ^{2} - 1}

What is the derivative of x^3+3x^2-9x+1 ?
The derivative of x^3+3x^2-9x+1 is 3x^2+6x-9
What is the first derivative of x^3+3x^2-9x+1 ?
The first derivative of x^3+3x^2-9x+1 is 3x^2+6x-9