What is the integral from pi/4 to x of sec^2(t) ?

The integral from pi/4 to x of sec^2(t) is tan(x)-1

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integral from pi/4 to x of sec^2(t)

\int_{\frac{π}{4}}^{x} sec^{2} (t) d t

tan (x) - 1

Solution steps

\int_{\frac{π}{4}}^{x} sec^{2} (t) d t

Use the common integral:

\int sec^{2} (t) d t = tan (t)

= [tan (t)]_{\frac{π}{4}}^{x}

Compute the boundaries:

tan (x) - 1

= tan (x) - 1

\int \frac{x + 1}{x ^{2} - 2 x - 1} d x

\int (2 t - 1)^{2} d t

\frac{d}{d x} (1 0^{t a n (π x)})

\frac{d}{d x} (3 \cdot cos (x))

x \to \frac{1}{2} lim (x sec (π x))

What is the integral from pi/4 to x of sec^2(t) ?
The integral from pi/4 to x of sec^2(t) is tan(x)-1