What is area y=(x-1)(x-2)(x-3),[0,3] ?

The answer to area y=(x-1)(x-2)(x-3),[0,3] is 11/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area y=(x-1)(x-2)(x-3),[0,3]

area

y = (x - 1) (x - 2) (x - 3), [0, 3]

\frac{11}{4}

Decimal Notation

2.75

Solution steps

Apply the area formula:

\int_{0}^{3} ∣ x - 1 ∣ ∣ x - 2 ∣ ∣ x - 3 ∣ d x

Solve

\int_{0}^{3} ∣ x - 1 ∣ ∣ x - 2 ∣ ∣ x - 3 ∣ d x : \frac{11}{4}

The area is:

= \frac{11}{4}

\int cos^{6} (θ) sin (2 θ) d θ

\int x 16 - 4 x^{2} d x

\frac{d}{d x} (5 ln (12 x))

x \to 0 lim (\frac{x ^{3} - 1}{x})

x \to 3 lim (\frac{2 x}{x - 3})

What is area y=(x-1)(x-2)(x-3),[0,3] ?
The answer to area y=(x-1)(x-2)(x-3),[0,3] is 11/4