What is the solution for (dy)/(dx)=e^{x+y-1}-1 ?

The solution for (dy)/(dx)=e^{x+y-1}-1 is y=-ln(-x-c_{1})-x+1

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(dy)/(dx)=e^{x+y-1}-1

\frac{d y}{d x} = e^{x + y - 1} - 1

y = - ln (- x - c_{1}) - x + 1

Solution steps

\frac{d y}{d x} = e^{x + y - 1} - 1

Solve using substitution:

y = - ln (- x - c_{1}) - x + 1

y = - ln (- x - c_{1}) - x + 1

x \to 3 lim (\frac{x + 5}{x - 3})

\frac{3 e ^{- 2 s}}{4 s ^{2} + 100}

\int \frac{arctan ( 9 x )}{1 + 81 x ^{2}} d x

\frac{d y}{d x} - 2 y = x

What is the solution for (dy)/(dx)=e^{x+y-1}-1 ?
The solution for (dy)/(dx)=e^{x+y-1}-1 is y=-ln(-x-c_{1})-x+1