What is the derivative of (8x+e^{-x^2}^2) ?

The derivative of (8x+e^{-x^2}^2) is 2(8x+e^{-x^2})(8-2e^{-x^2}x)

What is the first derivative of (8x+e^{-x^2}^2) ?

The first derivative of (8x+e^{-x^2}^2) is 2(8x+e^{-x^2})(8-2e^{-x^2}x)

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\frac{d}{d x} ((8 x + e^{- x^{2}})^{2})

2 (8 x + e^{- x^{2}}) (8 - 2 e^{- x^{2}} x)

Solution steps

\frac{d}{d x} ((8 x + e^{- x^{2}})^{2})

Apply the chain rule:

2 (8 x + e^{- x^{2}}) \frac{d}{d x} (8 x + e^{- x^{2}})

= 2 (8 x + e^{- x^{2}}) \frac{d}{d x} (8 x + e^{- x^{2}})

\frac{d}{d x} (8 x + e^{- x^{2}}) = 8 - 2 e^{- x^{2}} x

= 2 (8 x + e^{- x^{2}}) (8 - 2 e^{- x^{2}} x)

\frac{d}{d x} (x + \frac{100}{x})

(2 y^{2} + 4 x^{2}) d x - x y d y = 0

\frac{d x}{d y} + x y^{2} = 0

y = 5 + 4 - x, (0, 8)

\int \frac{x + 1}{x} d x

What is the derivative of (8x+e^{-x^2}^2) ?
The derivative of (8x+e^{-x^2}^2) is 2(8x+e^{-x^2})(8-2e^{-x^2}x)
What is the first derivative of (8x+e^{-x^2}^2) ?
The first derivative of (8x+e^{-x^2}^2) is 2(8x+e^{-x^2})(8-2e^{-x^2}x)