What is the limit as x approaches 2 of x^2+sqrt(7-x) ?

The limit as x approaches 2 of x^2+sqrt(7-x) is 4+sqrt(5)

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limit as x approaches 2 of x^2+sqrt(7-x)

x \to 2 lim (x^{2} + 7 - x)

4 + 5

Decimal Notation

6.23606 \dots

Solution steps

x \to 2 lim (x^{2} + 7 - x)

Plug in the value

x = 2

= 2^{2} + 7 - 2

Simplify

= 4 + 5

\frac{\partial}{\partial x} (y^{4} + 5 x y^{3})

\frac{d}{d x} (cos (5 x - 3))

\frac{- 2 x}{( x ^{2} - 1 ) ^{2}}

\int \frac{4 e ^{x}}{e ^{2 x} + 4 e ^{x} + 4} d x

\frac{d y}{d t} - \frac{1}{2} y = t y^{- 1}

What is the limit as x approaches 2 of x^2+sqrt(7-x) ?
The limit as x approaches 2 of x^2+sqrt(7-x) is 4+sqrt(5)