What is the tangent of f(x)=3e^x+2x,(0,3) ?

The tangent of f(x)=3e^x+2x,(0,3) is y=5x+3

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tangent of f(x)=3e^x+2x,(0,3)

tangent of

f (x) = 3 e^{x} + 2 x, (0, 3)

y = 5 x + 3

Solution steps

Find the slope of

f (x) = 3 e^{x} + 2 x : \frac{df ( x )}{d x} = 3 e^{x} + 2

Compute the slope of

f (x) = 3 e^{x} + 2 x

(0, 3) : m = 5

Find the line with slope m=

5

and passing through

(0, 3) : y = 5 x + 3

y = 5 x + 3

y^{^{'}} = \frac{( 2 x ^{4} + y ^{4} )}{x y ^{3}}

\int_{1}^{2} \frac{5 ln ( x )}{x ^{2}} d x

\frac{\partial}{\partial x} (t)

\frac{d}{d x} (\frac{( 3 x + 1 )}{tan ( x )})

2 x

What is the tangent of f(x)=3e^x+2x,(0,3) ?
The tangent of f(x)=3e^x+2x,(0,3) is y=5x+3