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Popular >

y^'=3+e^{-5t}

Solution

y^{^{'}} = 3 + e^{- 5 t}

Solution

y = 3 t - \frac{1}{5} e^{- 5 t} + c_{1}

Solution steps

y^{'} (t) = 3 + e^{- 5 t}

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int 3 + e^{- 5 t} d t

\int 3 + e^{- 5 t} d t = 3 t - \frac{1}{5} e^{- 5 t} + c_{1}

y = 3 t - \frac{1}{5} e^{- 5 t} + c_{1}

Popular Examples

(dy)/(dx)=e^{x-y},y(ln(3))=ln(5)

\frac{d y}{d x} = e^{x - y}, y (ln (3)) = ln (5)

(\partial)/(\partial y)(0.5x^2+y^2-3x+2y-5)

\frac{\partial}{\partial y} (0.5 x^{2} + y^{2} - 3 x + 2 y - 5)

simplify-5 simplify

- 5

derivative of ln(ax+b)

\frac{d}{d x} (ln (a x + b))

(\partial)/(\partial x)((0.9x)^{1/2})

\frac{\partial}{\partial x} ((0.9 x)^{\frac{1}{2}})

Frequently Asked Questions (FAQ)

What is the solution for y^'=3+e^{-5t} ?
The solution for y^'=3+e^{-5t} is y=3t-1/5 e^{-5t}+c_{1}