What is the derivative of x(x^2+9) ?

The derivative of x(x^2+9) is 3x^2+9

What is the first derivative of x(x^2+9) ?

The first derivative of x(x^2+9) is 3x^2+9

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derivative of

x (x^{2} + 9)

3 x^{2} + 9

Solution steps

\frac{d}{d x} (x (x^{2} + 9))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = x^{2} + 9

= \frac{d x}{d x} (x^{2} + 9) + \frac{d}{d x} (x^{2} + 9) x

\frac{d x}{d x} = 1

\frac{d}{d x} (x^{2} + 9) = 2 x

= 1 \cdot (x^{2} + 9) + 2 xx

Simplify

1 \cdot (x^{2} + 9) + 2 xx : 3 x^{2} + 9

= 3 x^{2} + 9

\frac{\partial}{\partial x} (sin (x e^{x^{2} y}))

\frac{\partial}{\partial x} (ln (x^{4} + y^{2}) - z)

2 sin (x) + sin^{2} (x)

3 x^{2} - 21 x

\frac{1 - 3 s}{s ^{2} + 8 s + 21}

What is the derivative of x(x^2+9) ?
The derivative of x(x^2+9) is 3x^2+9
What is the first derivative of x(x^2+9) ?
The first derivative of x(x^2+9) is 3x^2+9