What is the limit as n approaches infinity of 1-1/n ?

The limit as n approaches infinity of 1-1/n is 1

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limit as n approaches infinity of 1-1/n

n \to \infty lim (1 - \frac{1}{n})

1

Solution steps

n \to \infty lim (1 - \frac{1}{n})

x \to a lim [f (x) \pm g (x)] = x \to a lim f (x) \pm x \to a lim g (x)

With the exception of indeterminate form

= n \to \infty lim (1) - n \to \infty lim (\frac{1}{n})

n \to \infty lim (1) = 1

n \to \infty lim (\frac{1}{n}) = 0

= 1 - 0

Simplify

= 1

cos (x) - sin (x), x = 0, y = 0

\frac{\partial}{\partial x} (\frac{y}{x} + \frac{x}{y})

\frac{d}{d x} (\frac{7 x ^{2} - 6 x + 4}{3 x + 2})

\int (6 x + 2 y) d y

x \to 1 lim (x^{\frac{1}{( 1 - x )}})

What is the limit as n approaches infinity of 1-1/n ?
The limit as n approaches infinity of 1-1/n is 1