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Popular >

y^'=e^{x+2y}

Solution

y^{^{'}} = e^{x + 2 y}

Solution

y = - \frac{ln ( - 2 e ^{x} - c _{1} )}{2}

Solution steps

y^{'} (x) = e^{x + 2 y}

Solve separable ODE:

y = - \frac{ln ( - 2 e ^{x} - c _{1} )}{2}

y = - \frac{ln ( - 2 e ^{x} - c _{1} )}{2}

Popular Examples

7y^{''}+14y^'-21y=0

7 y^{^{''}} + 14 y^{^{'}} - 21 y = 0

limit as x approaches 0 of (x-2)/(x^2-4)

x \to 0 lim (\frac{x - 2}{x ^{2} - 4})

(\partial)/(\partial x)(x^3z-yx^2+z^2)

\frac{\partial}{\partial x} (x^{3} z - y x^{2} + z^{2})

limit as x approaches 3-of e^{x/(3-x)}

x \to 3 - lim (e^{\frac{x}{3 - x}})

limit as x approaches-0.01 of (e^x-1)/x

x \to - 0.01 lim (\frac{e ^{x} - 1}{x})

Frequently Asked Questions (FAQ)

What is the solution for y^'=e^{x+2y} ?
The solution for y^'=e^{x+2y} is y=-(ln(-2e^x-c_{1}))/2