What is the derivative of (cos(2x)^2) ?

The derivative of (cos(2x)^2) is -2sin(4x)

What is the first derivative of (cos(2x)^2) ?

The first derivative of (cos(2x)^2) is -2sin(4x)

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\frac{d}{d x} ((cos (2 x))^{2})

- 2 sin (4 x)

Solution steps

\frac{d}{d x} ((cos (2 x))^{2})

Apply the chain rule:

2 cos (2 x) \frac{d}{d x} (cos (2 x))

= 2 cos (2 x) \frac{d}{d x} (cos (2 x))

\frac{d}{d x} (cos (2 x)) = - sin (2 x) \cdot 2

= 2 cos (2 x) (- sin (2 x) \cdot 2)

Simplify

2 cos (2 x) (- sin (2 x) \cdot 2) : - 2 sin (4 x)

= - 2 sin (4 x)

\frac{4}{x}, 16 x, \frac{1}{4} x

\int \frac{x ^{2}}{( 144 + x ^{2} ) ^{2}} d x

x \to a lim (\frac{1}{- 6 - 4})

\int 18 cos^{2} (t) sin (t) d t

\frac{d}{d x} (arccsc (2 x + 1))

What is the derivative of (cos(2x)^2) ?
The derivative of (cos(2x)^2) is -2sin(4x)
What is the first derivative of (cos(2x)^2) ?
The first derivative of (cos(2x)^2) is -2sin(4x)