What is the derivative of f(x)=sqrt(8-x) ?

The derivative of f(x)=sqrt(8-x) is -1/(2sqrt(8-x))

What is the first derivative of f(x)=sqrt(8-x) ?

The first derivative of f(x)=sqrt(8-x) is -1/(2sqrt(8-x))

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derivative of

f (x) = 8 - x

- \frac{1}{2 8 - x}

Solution steps

\frac{d}{d x} (8 - x)

Apply the chain rule:

\frac{1}{2 8 - x} \frac{d}{d x} (8 - x)

= \frac{1}{2 8 - x} \frac{d}{d x} (8 - x)

\frac{d}{d x} (8 - x) = - 1

= \frac{1}{2 8 - x} (- 1)

Simplify

= - \frac{1}{2 8 - x}

x y^{^{'}} - y = 2 x^{2} y

y^{^{''}} + 18 y^{^{'}} + 81 y = t^{- 2} e^{- 9 t}

x \to - 5 lim (\frac{x ^{2} - 2}{x + 5})

\int \frac{1}{( x + 1 ) ( x ^{2} + 4 )} d x

- 6 y^{^{''}} + 54 y^{^{'}} = 0, y (2) = 1, y^{^{'}} (- 1) = 1

What is the derivative of f(x)=sqrt(8-x) ?
The derivative of f(x)=sqrt(8-x) is -1/(2sqrt(8-x))
What is the first derivative of f(x)=sqrt(8-x) ?
The first derivative of f(x)=sqrt(8-x) is -1/(2sqrt(8-x))