What is the derivative of 5\sqrt[3]{x}+x^3 ?

The derivative of 5\sqrt[3]{x}+x^3 is (5+9x^{8/3})/(3x^{2/3)}

What is the first derivative of 5\sqrt[3]{x}+x^3 ?

The first derivative of 5\sqrt[3]{x}+x^3 is (5+9x^{8/3})/(3x^{2/3)}

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\frac{5 + 9 x ^{\frac{8}{3}}}{3 x ^{\frac{2}{3}}}

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d x} (x^{3}) = 3 x^{2}

= \frac{5}{3 x ^{\frac{2}{3}}} + 3 x^{2}

Simplify

\frac{5}{3 x ^{\frac{2}{3}}} + 3 x^{2} : \frac{5 + 9 x ^{\frac{8}{3}}}{3 x ^{\frac{2}{3}}}

= \frac{5 + 9 x ^{\frac{8}{3}}}{3 x ^{\frac{2}{3}}}

f (x) = (3 t - 1)^{4} (2 t + 1)^{- 3}

\int \frac{1}{( 4 - x ) ^{\frac{3}{2}}} d x

n = 1 \sum \infty \frac{5 n}{4 n + 7}

\frac{8}{( s ^{2} + 1 ) ( s ^{2} - 1 )}

What is the derivative of 5\sqrt[3]{x}+x^3 ?
The derivative of 5\sqrt[3]{x}+x^3 is (5+9x^{8/3})/(3x^{2/3)}
What is the first derivative of 5\sqrt[3]{x}+x^3 ?
The first derivative of 5\sqrt[3]{x}+x^3 is (5+9x^{8/3})/(3x^{2/3)}