What is the sum from n=0 to infinity of 1/(n^{-1)} ?

The sum from n=0 to infinity of 1/(n^{-1)} is diverges

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sum from n=0 to infinity of 1/(n^{-1)}

n = 0 \sum \infty \frac{1}{n ^{- 1}}

diverges

Solution steps

n = 1 \sum \infty \frac{1}{n ^{- 1}}

Apply Series Divergence Test:

diverges

= diverges

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What is the sum from n=0 to infinity of 1/(n^{-1)} ?
The sum from n=0 to infinity of 1/(n^{-1)} is diverges