What is the integral of 1/(θ^2)cos(1/θ) ?

The integral of 1/(θ^2)cos(1/θ) is -sin(1/θ)+C

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integral of 1/(θ^2)cos(1/θ)

\int \frac{1}{θ ^{2}} cos (\frac{1}{θ}) d θ

- sin (\frac{1}{θ}) + C

Solution steps

\int \frac{1}{θ ^{2}} cos (\frac{1}{θ}) d θ

Apply u-substitution

: \int - cos (u) d u

= \int - cos (u) d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int cos (u) d u

Use the common integral:

\int cos (u) d u = sin (u)

= - sin (u)

Substitute back

u = \frac{1}{θ}

= - sin (\frac{1}{θ})

Add a constant to the solution

= - sin (\frac{1}{θ}) + C

\frac{\partial}{\partial x} (e^{s i n (2 x)})

\frac{d}{d x} (e^{t a n h (x)})

1 + x

\frac{d y}{d x} = - \frac{5 y}{50 + x}

y = e^{7 e^{x}}

What is the integral of 1/(θ^2)cos(1/θ) ?
The integral of 1/(θ^2)cos(1/θ) is -sin(1/θ)+C