What is the integral of (arccos(sqrt(x)))/(sqrt(x)) ?

The integral of (arccos(sqrt(x)))/(sqrt(x)) is 2sqrt(x)arccos(sqrt(x))-2sqrt(1-x)+C

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integral of (arccos(sqrt(x)))/(sqrt(x))

\int \frac{arccos ( x )}{x} d x

2 x arccos (x) - 2 1 - x + C

Solution steps

\int \frac{arccos ( x )}{x} d x

Apply Integration By Parts

: 2 x arccos (x) - \int - \frac{1}{1 - x} d x

= 2 x arccos (x) - \int - \frac{1}{1 - x} d x

\int - \frac{1}{1 - x} d x = 2 1 - x

= 2 x arccos (x) - 2 1 - x

Add a constant to the solution

= 2 x arccos (x) - 2 1 - x + C

\frac{d}{d x} (2 sin (x) + sin^{2} (x))

\frac{d}{d X} ((X - 3)^{2} + 2)

f (x) = \frac{3 x}{x ^{2} + 1}

\int (x - \frac{1}{x}) d x

\frac{x + 1}{x + 3}

What is the integral of (arccos(sqrt(x)))/(sqrt(x)) ?
The integral of (arccos(sqrt(x)))/(sqrt(x)) is 2sqrt(x)arccos(sqrt(x))-2sqrt(1-x)+C