What is (\partial)/(\partial x)(200(y-x^2)) ?

The answer to (\partial)/(\partial x)(200(y-x^2)) is -400x

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(\partial)/(\partial x)(200(y-x^2))

\frac{\partial}{\partial x} (200 (y - x^{2}))

- 400 x

Solution steps

\frac{\partial}{\partial x} (200 (y - x^{2}))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 200 \frac{\partial}{\partial x} (y - x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= 200 (\frac{\partial}{\partial x} (y) - \frac{\partial}{\partial x} (x^{2}))

\frac{\partial}{\partial x} (y) = 0

\frac{\partial}{\partial x} (x^{2}) = 2 x

= 200 (0 - 2 x)

Simplify

= - 400 x

x \to - 2 lim (\frac{x - 1}{x ^{2} - 4})

\int \frac{2 x}{x ^{3}} d x

\int_{- \frac{1}{2}}^{\frac{3}{2}} x - cos (π x) d x

\int sin (x) cos (\frac{1}{2} x) d x

\frac{d y}{d x} = (- y)

What is (\partial)/(\partial x)(200(y-x^2)) ?
The answer to (\partial)/(\partial x)(200(y-x^2)) is -400x