What is the derivative of x^2+(128/x) ?

The derivative of x^2+(128/x) is 2x-(128)/(x^2)

What is the first derivative of x^2+(128/x) ?

The first derivative of x^2+(128/x) is 2x-(128)/(x^2)

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\frac{d}{d x} (x^{2} + \frac{128}{x})

2 x - \frac{128}{x ^{2}}

Solution steps

\frac{d}{d x} (x^{2} + \frac{128}{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (\frac{128}{x})

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (\frac{128}{x}) = - \frac{128}{x ^{2}}

= 2 x - \frac{128}{x ^{2}}

y^{^{'''}} + 8 y^{^{''}} = - 6 x^{2} + 9 x + 2

ln (sec (2 x) + tan (2 x))

y^{^{'}} = (t + y) 2 - 1

\int - 6 sin (6 x) d x

\int \frac{x + 2}{x ^{2} + 9} d x

What is the derivative of x^2+(128/x) ?
The derivative of x^2+(128/x) is 2x-(128)/(x^2)
What is the first derivative of x^2+(128/x) ?
The first derivative of x^2+(128/x) is 2x-(128)/(x^2)