What is the solution for (4x^2+3y^2)dx-2xydy=0 ?

The solution for (4x^2+3y^2)dx-2xydy=0 is y=xsqrt(-4+c_{1)x},y=-xsqrt(-4+c_{1)x}

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(4x^2+3y^2)dx-2xydy=0

(4 x^{2} + 3 y^{2}) d x - 2 x y d y = 0

y = x - 4 + c_{1} x, y = - x - 4 + c_{1} x

Solution steps

(4 x^{2} + 3 y^{2}) d x - 2 x y d y = 0

Solve Bernoulli ODE:

y = x - 4 + c_{1} x, y = - x - 4 + c_{1} x

y = x - 4 + c_{1} x, y = - x - 4 + c_{1} x

\int_{1}^{5} x^{3} ln (4 x) d x

\int \frac{( x + 1 ) ( x - 2 )}{x} d x

\frac{\partial}{\partial y} (x^{2} y + y z^{3} + z^{5} x)

\frac{d}{d x} ((x + \frac{1}{x}) (x - \frac{1}{x}))

y^{^{''}} + 10 y^{^{'}} + 25 = 0

What is the solution for (4x^2+3y^2)dx-2xydy=0 ?
The solution for (4x^2+3y^2)dx-2xydy=0 is y=xsqrt(-4+c_{1)x},y=-xsqrt(-4+c_{1)x}