What is the derivative of sqrt(4x-16) ?

The derivative of sqrt(4x-16) is 1/(sqrt(x-4))

What is the first derivative of sqrt(4x-16) ?

The first derivative of sqrt(4x-16) is 1/(sqrt(x-4))

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derivative of

4 x - 16

\frac{1}{x - 4}

Solution steps

\frac{d}{d x} (4 x - 16)

Apply the chain rule:

\frac{1}{2 4 x - 16} \frac{d}{d x} (4 x - 16)

= \frac{1}{2 4 x - 16} \frac{d}{d x} (4 x - 16)

\frac{d}{d x} (4 x - 16) = 4

= \frac{1}{2 4 x - 16} \cdot 4

Simplify

\frac{1}{2 4 x - 16} \cdot 4 : \frac{1}{x - 4}

= \frac{1}{x - 4}

y^{^{''}} + 10 y^{^{'}} + 20 y = 0

\frac{1}{( s - 2 ) ( s + 2 )}

n = 0 \sum \infty 2 (\frac{2}{3})^{n}

n = 1 \sum \infty \frac{n}{2}

5 sin^{2} (x)

What is the derivative of sqrt(4x-16) ?
The derivative of sqrt(4x-16) is 1/(sqrt(x-4))
What is the first derivative of sqrt(4x-16) ?
The first derivative of sqrt(4x-16) is 1/(sqrt(x-4))