What is taylor x^2cos(x)0.1 ?

The answer to taylor x^2cos(x)0.1 is 0.1x^2-0.05x^4+1/240 x^6-0.00013…x^8+1/403200 x^{10}+\ldots

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

taylor x^2cos(x)0.1

taylor

x^{2} cos (x) 0.1

0.1 x^{2} - 0.05 x^{4} + \frac{1}{240} x^{6} - 0.00013 \dots x^{8} + \frac{1}{403200} x^{10} + \dots

Solution steps

Apply the Taylor Formula

= 0 + \frac{\frac{d}{d x} ( x ^{2} cos ( x ) \cdot 0.1 ) ( 0 )}{1 !} x + \frac{\frac{d ^{2}}{d x ^{2}} ( x ^{2} cos ( x ) \cdot 0.1 ) ( 0 )}{2 !} x^{2} + \frac{\frac{d ^{3}}{d x ^{3}} ( x ^{2} cos ( x ) \cdot 0.1 ) ( 0 )}{3 !} x^{3} + \dots

Evaluate Derivatives

= 0 + \frac{0}{1 !} x + \frac{0.2}{2 !} x^{2} + \frac{0}{3 !} x^{3} + \frac{- 1.2}{4 !} x^{4} + \frac{0}{5 !} x^{5} + \frac{3}{6 !} x^{6} + \frac{0}{7 !} x^{7} + \frac{- 5.6}{8 !} x^{8} + \frac{0}{9 !} x^{9} + \frac{9}{10 !} x^{10} + \dots

Refine

= 0.1 x^{2} - 0.05 x^{4} + \frac{1}{240} x^{6} - 0.00013 \dots x^{8} + \frac{1}{403200} x^{10} + \dots

\int \frac{4}{x ^{3}} d x

\frac{\partial}{\partial y} (y^{2} z^{3})

\int_{1}^{2} x^{2} ln (x) d x

f (x) = (3 x^{4} + 7)^{6}

\frac{d}{d x} (\frac{2 x ^{3}}{( x ^{2} + 1 ) ^{2}})

What is taylor x^2cos(x)0.1 ?
The answer to taylor x^2cos(x)0.1 is 0.1x^2-0.05x^4+1/240 x^6-0.00013…x^8+1/403200 x^{10}+\ldots