en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'=2e^{2x-y},y(0)=0

Solution

y^{^{'}} = 2 e^{2 x - y}, y (0) = 0

Solution

y = 2 x

Solution steps

y^{'} (x) = 2 e^{2 x - y}

Solve separable ODE:

y = 2 x

y = 2 x

Popular Examples

derivative of x^3-x^2+7x-1

\frac{d}{d x} (x^{3} - x^{2} + 7 x - 1)

integral of 2*cos(x)

\int 2 \cdot cos (x) d x

limit as h approaches 0 of (cos(h)-1)/h

h \to 0 lim (\frac{cos ( h ) - 1}{h})

limit as x approaches 1 of e^{-x}

x \to 1 lim (e^{- x})

tangent of f(x)=(2x-1)(x+2),\at x=(1.3)tangent of

f (x) = (2 x - 1) (x + 2), at x = (1.3)

Frequently Asked Questions (FAQ)

What is the solution for y^'=2e^{2x-y},y(0)=0 ?
The solution for y^'=2e^{2x-y},y(0)=0 is y=2x