What is the solution for y^'=(x^2-y^2)/(xy),y(2)=3 ?

The solution for y^'=(x^2-y^2)/(xy),y(2)=3 is y=(sqrt(x^4+56))/(sqrt(2)x)

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y^'=(x^2-y^2)/(xy),y(2)=3

y^{^{'}} = \frac{x ^{2} - y ^{2}}{x y}, y (2) = 3

y = \frac{x ^{4} + 56}{2 x}

Solution steps

y^{'} (x) = \frac{x ^{2} - y ^{2}}{x y}

Solve Bernoulli ODE:

y = \frac{x ^{4} + 56}{2 x}

y = \frac{x ^{4} + 56}{2 x}

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What is the solution for y^'=(x^2-y^2)/(xy),y(2)=3 ?
The solution for y^'=(x^2-y^2)/(xy),y(2)=3 is y=(sqrt(x^4+56))/(sqrt(2)x)