What is area x,x^3-3x^2+3x,-0,1 ?

The answer to area x,x^3-3x^2+3x,-0,1 is 1/4

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area x,x^3-3x^2+3x,-0,1

area

x, x^{3} - 3 x^{2} + 3 x, - 0, 1

\frac{1}{4}

Decimal Notation

0.25

Solution steps

Apply the area formula:

\int_{- 0}^{1} x - (x^{3} - 3 x^{2} + 3 x) d x

Solve

\int_{- 0}^{1} x - (x^{3} - 3 x^{2} + 3 x) d x : \frac{1}{4}

The area is:

= \frac{1}{4}

\frac{- 5 x}{2 x - 1}

e^{b x}

\int_{0}^{x} \frac{1}{x ^{2}} d x

\frac{d}{d x} (sin^{4} (3 x))

\int r^{2} (\frac{r ^{3}}{24} - 6)^{7} d r