What is laplacetransform sin(t+2) ?

The answer to laplacetransform sin(t+2) is (sin(2)s+cos(2))/(s^2+1)

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laplacetransform sin(t+2)

laplace transform

sin (t + 2)

\frac{sin ( 2 ) s + cos ( 2 )}{s ^{2} + 1}

Solution steps

L {sin (t + 2)}

Use Laplace Transform table:

L {sin (a t + b)} = \frac{s \cdot sin ( b ) + a \cdot cos ( b )}{s ^{2} + a ^{2}}

L {sin (t + 2)} = \frac{s sin ( 2 ) + 1 \cdot cos ( 2 )}{s ^{2} + 1 ^{2}}

= \frac{s sin ( 2 ) + 1 \cdot cos ( 2 )}{s ^{2} + 1 ^{2}}

= \frac{sin ( 2 ) s + cos ( 2 )}{s ^{2} + 1}

f (x) = \frac{6}{x - 1}, (3, 3)

y = 6 x^{2} - 7 x + 4, (1, 3)

sin (3 x) cos (2 x)

\int sin^{4} (2 x) cos^{2} (2 x) d x

\int 3 sin (5 x) d x

What is laplacetransform sin(t+2) ?
The answer to laplacetransform sin(t+2) is (sin(2)s+cos(2))/(s^2+1)