What is the sum from n=0 to infinity of n(2/7)^n ?

The sum from n=0 to infinity of n(2/7)^n is converges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=0 to infinity of n(2/7)^n

n = 0 \sum \infty n (\frac{2}{7})^{n}

converges

Solution steps

n = 0 \sum \infty n (\frac{2}{7})^{n}

Apply Series Ratio Test:

converges

= converges

\frac{\partial}{\partial x} ((x^{3} + y^{2})^{5})

\int_{0}^{\frac{π}{2}} 20 cos^{5} (x) d x

\int_{1}^{2} (\frac{6}{x ^{3}} + 2 x) d x

x \to 2 lim (x^{3} - x^{2} + 2 x)

\frac{1}{2 s ^{2} + 10 s + 12}

What is the sum from n=0 to infinity of n(2/7)^n ?
The sum from n=0 to infinity of n(2/7)^n is converges