What is the solution for y^{''}-8y^'+17=0 ?

The solution for y^{''}-8y^'+17=0 is y=c_{1}e^{8t}+c_{2}+(17t)/8

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y^{''}-8y^'+17=0

y^{^{''}} - 8 y^{^{'}} + 17 = 0

y = c_{1} e^{8 t} + c_{2} + \frac{17 t}{8}

Solution steps

y^{''} (t) - 8 y^{'} (t) + 17 = 0

Solve linear ODE:

y = c_{1} e^{8 t} + c_{2} + \frac{17 t}{8}

y = c_{1} e^{8 t} + c_{2} + \frac{17 t}{8}

U (x) = - 0.04 x^{2} + 240 x - 10000

\int_{0}^{3} e^{x} - x^{2} d x

\frac{\partial}{\partial x} (y ln (x^{3} + y^{4} + 3) - 9)

x \to 2 lim (x^{2} - x + 2)

y^{^{'}} = t - t y

What is the solution for y^{''}-8y^'+17=0 ?
The solution for y^{''}-8y^'+17=0 is y=c_{1}e^{8t}+c_{2}+(17t)/8