What is the tangent of y=sin(2x)+sin^2(2x),(0,0) ?

The tangent of y=sin(2x)+sin^2(2x),(0,0) is y=2x

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tangent of y=sin(2x)+sin^2(2x),(0,0)

tangent of

y = sin (2 x) + sin^{2} (2 x), (0, 0)

y = 2 x

Solution steps

Find the slope of

y = sin (2 x) + sin^{2} (2 x) : \frac{d y}{d x} = cos (2 x) \cdot 2 + 2 sin (4 x)

Compute the slope of

y = sin (2 x) + sin^{2} (2 x)

(0, 0) : m = 2

Find the line with slope m=

2

and passing through

(0, 0) : y = 2 x

y = 2 x

\frac{\partial}{\partial x} (10 x + y)

f (x) = \frac{2}{x}, (- 5, - \frac{2}{5})

(x^{2} + 3 x - 1) (2 - x)

\frac{\partial}{\partial x} (1 - x)

\frac{\partial}{\partial x} (\frac{x}{x ^{2} - y ^{2}})

What is the tangent of y=sin(2x)+sin^2(2x),(0,0) ?
The tangent of y=sin(2x)+sin^2(2x),(0,0) is y=2x