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Popular >

y^'= 1/(y-x)

Solution

y^{^{'}} = \frac{1}{y - x}

Solution

y = W (\frac{c _{1}}{e ^{x + 1}}) + x + 1

Solution steps

y^{'} (x) = \frac{1}{y - x}

Solve exact ODE:

y = W (\frac{c _{1}}{e ^{x + 1}}) + x + 1

y = W (\frac{c _{1}}{e ^{x + 1}}) + x + 1

Popular Examples

integral of (12x+2)sqrt(6x^2+2x)

\int (12 x + 2) 6 x^{2} + 2 x d x

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\int x e^{- 3 x^{2}} d x

integral from 0 to 2 of 1/(x^2-2x+2)

\int_{0}^{2} \frac{1}{x ^{2} - 2 x + 2} d x

integral of 1/(a+bx^2)

\int \frac{1}{a + b x ^{2}} d x

integral of (sin(x))^2cos(x)

\int (sin (x))^{2} cos (x) d x

Frequently Asked Questions (FAQ)

What is the solution for y^'= 1/(y-x) ?
The solution for y^'= 1/(y-x) is y=\W((c_{1})/(e^{x+1)})+x+1