What is the limit as x approaches 0 of 0/(2x^2) ?

The limit as x approaches 0 of 0/(2x^2) is 0

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limit as x approaches 0 of 0/(2x^2)

x \to 0 lim (\frac{0}{2 x ^{2}})

0

Solution steps

x \to 0 lim (\frac{0}{2 x ^{2}})

x \to a - lim f (x) = x \to a + lim f (x) = L

then

x \to a lim f (x) = L

x \to 0 - lim (\frac{0}{2 x ^{2}}) = 0

x \to 0 + lim (\frac{0}{2 x ^{2}}) = 0

= 0

\frac{d y}{d t} = sin (t) - y, y (0) = - 1

(x + 1)^{\frac{2}{3}} \frac{d y}{d x} = y^{\frac{1}{3}}

f (x) = \frac{x}{x ^{2} + 49}

\int_{0}^{1} \frac{4}{1 + t ^{2}} d t

ln (1 + x^{2})

What is the limit as x approaches 0 of 0/(2x^2) ?
The limit as x approaches 0 of 0/(2x^2) is 0