What is the tangent of y=(10x)/(x^2-6),(4,4) ?

The tangent of y=(10x)/(x^2-6),(4,4) is y=-11/5 x+64/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of y=(10x)/(x^2-6),(4,4)

tangent of

y = \frac{10 x}{x ^{2} - 6}, (4, 4)

y = - \frac{11}{5} x + \frac{64}{5}

Solution steps

Find the slope of

y = \frac{10 x}{x ^{2} - 6} : \frac{d y}{d x} = \frac{10 ( - x ^{2} - 6 )}{( x ^{2} - 6 ) ^{2}}

Compute the slope of

y = \frac{10 x}{x ^{2} - 6}

(4, 4) : m = - \frac{11}{5}

Find the line with slope m=

- \frac{11}{5}

and passing through

(4, 4) : y = - \frac{11}{5} x + \frac{64}{5}

y = - \frac{11}{5} x + \frac{64}{5}

x \to 1 lim (\frac{ln ( x )}{x - 1})

\int - 20 x d x

t y^{^{'}} + 2 y + t = 0

\int + cos (θ) cos^{5} (sin (θ)) d θ

x^{^{'}} = \frac{1}{x ^{2}}, x (1) = 1

What is the tangent of y=(10x)/(x^2-6),(4,4) ?
The tangent of y=(10x)/(x^2-6),(4,4) is y=-11/5 x+64/5