What is (\partial)/(\partial x)(x^8y^5-x^7y^4) ?

The answer to (\partial)/(\partial x)(x^8y^5-x^7y^4) is 8y^5x^7-7y^4x^6

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(\partial)/(\partial x)(x^8y^5-x^7y^4)

\frac{\partial}{\partial x} (x^{8} y^{5} - x^{7} y^{4})

8 y^{5} x^{7} - 7 y^{4} x^{6}

Solution steps

\frac{\partial}{\partial x} (x^{8} y^{5} - x^{7} y^{4})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{8} y^{5}) - \frac{\partial}{\partial x} (x^{7} y^{4})

\frac{\partial}{\partial x} (x^{8} y^{5}) = 8 y^{5} x^{7}

\frac{\partial}{\partial x} (x^{7} y^{4}) = 7 y^{4} x^{6}

= 8 y^{5} x^{7} - 7 y^{4} x^{6}

4^{x^{3}}

\frac{d}{d x} (x coth (6 + x^{2}))

\int \frac{e ^{x}}{( x - 1 )} d x

y^{^{'}} = - \frac{π}{2} t (1 + y^{2})

What is (\partial)/(\partial x)(x^8y^5-x^7y^4) ?
The answer to (\partial)/(\partial x)(x^8y^5-x^7y^4) is 8y^5x^7-7y^4x^6