What is (d^2)/(dx^2)((x^2+1)/(x^2-1)) ?

The answer to (d^2)/(dx^2)((x^2+1)/(x^2-1)) is -(4(-3x^2-1))/((x^2-1)^3)

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(d^2)/(dx^2)((x^2+1)/(x^2-1))

\frac{d ^{2}}{d x ^{2}} (\frac{x ^{2} + 1}{x ^{2} - 1})

- \frac{4 ( - 3 x ^{2} - 1 )}{( x ^{2} - 1 ) ^{3}}

Solution steps

\frac{d ^{2}}{d x ^{2}} (\frac{x ^{2} + 1}{x ^{2} - 1})

\frac{d}{d x} (\frac{x ^{2} + 1}{x ^{2} - 1}) = - \frac{4 x}{( x ^{2} - 1 ) ^{2}}

= \frac{d}{d x} (- \frac{4 x}{( x ^{2} - 1 ) ^{2}})

\frac{d}{d x} (- \frac{4 x}{( x ^{2} - 1 ) ^{2}}) = - \frac{4 ( - 3 x ^{2} - 1 )}{( x ^{2} - 1 ) ^{3}}

= - \frac{4 ( - 3 x ^{2} - 1 )}{( x ^{2} - 1 ) ^{3}}

\frac{\partial}{\partial x} ((x - 4)^{2} + y^{2})

(2 x + y cos (x y)) d x + x cos (x y) d y = 0

\frac{\partial}{\partial x} (x^{9} y^{4} - x^{8} y^{3})

x y^{^{'}} = y + x sin (x)

y^{^{''}} + 2 y^{^{'}} + 5 y = 0

What is (d^2)/(dx^2)((x^2+1)/(x^2-1)) ?
The answer to (d^2)/(dx^2)((x^2+1)/(x^2-1)) is -(4(-3x^2-1))/((x^2-1)^3)