What is the derivative of sqrt(9+x^2) ?

The derivative of sqrt(9+x^2) is x/(sqrt(9+x^2))

What is the first derivative of sqrt(9+x^2) ?

The first derivative of sqrt(9+x^2) is x/(sqrt(9+x^2))

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\frac{d}{d x} (9 + x^{2})

\frac{x}{9 + x ^{2}}

Solution steps

\frac{d}{d x} (9 + x^{2})

Apply the chain rule:

\frac{1}{2 9 + x ^{2}} \frac{d}{d x} (9 + x^{2})

= \frac{1}{2 9 + x ^{2}} \frac{d}{d x} (9 + x^{2})

\frac{d}{d x} (9 + x^{2}) = 2 x

= \frac{1}{2 9 + x ^{2}} \cdot 2 x

Simplify

\frac{1}{2 9 + x ^{2}} \cdot 2 x : \frac{x}{9 + x ^{2}}

= \frac{x}{9 + x ^{2}}

\frac{d}{d x} (e^{x^{4} y})

\int x^{3} (5 + x^{4})^{11} d x

\int_{x^{3}}^{x^{4}} (2 t - 1)^{3} d t

\int (3) d x

f (x) = \frac{60}{0.01 x ^{2} + 1}

What is the derivative of sqrt(9+x^2) ?
The derivative of sqrt(9+x^2) is x/(sqrt(9+x^2))
What is the first derivative of sqrt(9+x^2) ?
The first derivative of sqrt(9+x^2) is x/(sqrt(9+x^2))