What is the solution for (t^2-20t+75)(dy)/(dt)=y ?

The solution for (t^2-20t+75)(dy)/(dt)=y is y=(c_{1}\sqrt[10]{t-15})/(\sqrt[10]{t-5)}

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(t^2-20t+75)(dy)/(dt)=y

(t^{2} - 20 t + 75) \frac{d y}{d t} = y

Solution steps

(t^{2} - 20 t + 75) \frac{d y}{d t} = y

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What is the solution for (t^2-20t+75)(dy)/(dt)=y ?
The solution for (t^2-20t+75)(dy)/(dt)=y is y=(c_{1}\sqrt[10]{t-15})/(\sqrt[10]{t-5)}