What is the integral from 0 to 1 of (57)/(x^5) ?

The integral from 0 to 1 of (57)/(x^5) is diverges

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integral from 0 to 1 of (57)/(x^5)

\int_{0}^{1} \frac{57}{x ^{5}} d x

diverges

Solution steps

\int_{0}^{1} \frac{57}{x ^{5}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 57 \cdot \int_{0}^{1} \frac{1}{x ^{5}} d x

Apply the Power Rule

: [- \frac{1}{4 x ^{4}}]_{0}^{1}

= 57 [- \frac{1}{4 x ^{4}}]_{0}^{1}

Compute the boundaries:

diverges

= diverges

\int \frac{2 x}{( x ^{3} - 1 )} d x

n = 0 \sum \infty (- 4)^{n}

x + \frac{1}{x ^{3}}

\int \frac{1}{64 e ^{- 6 x} + e ^{6 x}} d x

\frac{d}{d x} (2 sec (\frac{x}{2}))

What is the integral from 0 to 1 of (57)/(x^5) ?
The integral from 0 to 1 of (57)/(x^5) is diverges