What is the integral from 0.1 to 0.2 of 600x ?

The integral from 0.1 to 0.2 of 600x is 9

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integral from 0.1 to 0.2 of 600x

\int_{0.1}^{0.2} 600 x d x

9

Solution steps

\int_{0.1}^{0.2} 600 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 600 \cdot \int_{0.1}^{0.2} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0.1}^{0.2}

= 600 [\frac{x ^{2}}{2}]_{0.1}^{0.2}

Simplify

= 600 [0.5 x^{2}]_{0.1}^{0.2}

Compute the boundaries:

0.015

= 600 \cdot 0.015

Simplify

= 9

x \to \infty lim (x - 3)

\int \frac{1}{cos ^{2} ( θ )} d θ

y = e^{x} x^{5} + 10 e^{x} x^{4} + 20 e^{x} x^{3}

\frac{d y}{d t} = 0.225 - \frac{y}{200}

\frac{d}{d x} (e^{e})

What is the integral from 0.1 to 0.2 of 600x ?
The integral from 0.1 to 0.2 of 600x is 9