What is the tangent of y=x^2-2,(5,23) ?

The tangent of y=x^2-2,(5,23) is y=10x-27

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tangent of y=x^2-2,(5,23)

tangent of

y = x^{2} - 2, (5, 23)

y = 10 x - 27

Solution steps

Find the slope of

y = x^{2} - 2 : \frac{d y}{d x} = 2 x

Compute the slope of

y = x^{2} - 2

(5, 23) : m = 10

Find the line with slope m=

10

and passing through

(5, 23) : y = 10 x - 27

y = 10 x - 27

x \to 1 + lim (x^{\frac{1}{1 - x}})

\int \frac{2 x}{1 - x ^{2}} d x

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\int_{4}^{20} \frac{1}{16}

\int \frac{1}{[ ( x ^{2} - 9 ) ^{2} ]} d x

What is the tangent of y=x^2-2,(5,23) ?
The tangent of y=x^2-2,(5,23) is y=10x-27