What is the tangent of x^2+y^2=25,(-3,4) ?

The tangent of x^2+y^2=25,(-3,4) is y= 3/4 x+25/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of x^2+y^2=25,(-3,4)

tangent of

x^{2} + y^{2} = 25, (- 3, 4)

y = \frac{3}{4} x + \frac{25}{4}

Solution steps

Find the slope of

x^{2} + y^{2} = 25 : \frac{d y}{d x} = - \frac{x}{y}

Compute the slope of

x^{2} + y^{2} = 25

(- 3, 4) : m = \frac{3}{4}

Find the line with slope m=

\frac{3}{4}

and passing through

(- 3, 4) : y = \frac{3}{4} x + \frac{25}{4}

y = \frac{3}{4} x + \frac{25}{4}

\frac{d}{d x} (x^{3} (1 - x)^{2})

\int x sec^{2} (x) d x

\int \frac{sec ^{2} ( 3 ) t}{t} d t

y = \frac{6 x ^{2} + 2 x + 2}{x}

\frac{d}{d x} (ln (4 x^{3} - x^{2}))

What is the tangent of x^2+y^2=25,(-3,4) ?
The tangent of x^2+y^2=25,(-3,4) is y= 3/4 x+25/4