What is the derivative of f(x)=(-5x)/(1-x) ?

The derivative of f(x)=(-5x)/(1-x) is -5/((1-x)^2)

What is the first derivative of f(x)=(-5x)/(1-x) ?

The first derivative of f(x)=(-5x)/(1-x) is -5/((1-x)^2)

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derivative of

f (x) = \frac{- 5 x}{1 - x}

- \frac{5}{( 1 - x ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{- 5 x}{1 - x})

Simplify

\frac{- 5 x}{1 - x} : - \frac{5 x}{1 - x}

= \frac{d}{d x} (- \frac{5 x}{1 - x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 5 \frac{d}{d x} (\frac{x}{1 - x})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= - 5 \cdot \frac{\frac{d x}{d x} ( 1 - x ) - \frac{d}{d x} ( 1 - x ) x}{( 1 - x ) ^{2}}

\frac{d x}{d x} = 1

\frac{d}{d x} (1 - x) = - 1

= - 5 \cdot \frac{1 \cdot ( 1 - x ) - ( - 1 ) x}{( 1 - x ) ^{2}}

Simplify

- 5 \cdot \frac{1 \cdot ( 1 - x ) - ( - 1 ) x}{( 1 - x ) ^{2}} : - \frac{5}{( 1 - x ) ^{2}}

= - \frac{5}{( 1 - x ) ^{2}}

\frac{d}{d x} (a t^{m} + b t^{m + n})

\frac{d}{d x} (sin (x) sin (3 x))

4 x^{2} - 2 x + 4

\frac{\partial}{\partial x} (3 x^{2} + 6 x y^{3})

7 - 4 t

What is the derivative of f(x)=(-5x)/(1-x) ?
The derivative of f(x)=(-5x)/(1-x) is -5/((1-x)^2)
What is the first derivative of f(x)=(-5x)/(1-x) ?
The first derivative of f(x)=(-5x)/(1-x) is -5/((1-x)^2)