What is the derivative of 8x^3e^{-x} ?

The derivative of 8x^3e^{-x} is 8(3e^{-x}x^2-e^{-x}x^3)

What is the first derivative of 8x^3e^{-x} ?

The first derivative of 8x^3e^{-x} is 8(3e^{-x}x^2-e^{-x}x^3)

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\frac{d}{d x} (8 x^{3} e^{- x})

8 (3 e^{- x} x^{2} - e^{- x} x^{3})

Solution steps

\frac{d}{d x} (8 x^{3} e^{- x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 8 \frac{d}{d x} (x^{3} e^{- x})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{3}, g = e^{- x}

= 8 (\frac{d}{d x} (x^{3}) e^{- x} + \frac{d}{d x} (e^{- x}) x^{3})

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (e^{- x}) = - e^{- x}

= 8 (3 x^{2} e^{- x} + (- e^{- x}) x^{3})

Simplify

= 8 (3 e^{- x} x^{2} - e^{- x} x^{3})

\frac{d}{d x} (x e^{k x})

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\int sin (x) - 4 cos (x) d x

y = 7^{5 x + 4}

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What is the derivative of 8x^3e^{-x} ?
The derivative of 8x^3e^{-x} is 8(3e^{-x}x^2-e^{-x}x^3)
What is the first derivative of 8x^3e^{-x} ?
The first derivative of 8x^3e^{-x} is 8(3e^{-x}x^2-e^{-x}x^3)